@emperorthanos-: Character Update?

## DarkDementor101's forum posts

@lan_fan: Okay?

@darkdementor101: sorry for sounding aggressive

No problem!

Okay, back again and I'm taking another go at yet another characters speed! This time it is a fox character so I hope it all comes out well. Again, if you wish to disagree with my calculations go ahead and do so, but at least provide reasons so that I can improve my analysis in future time and remove any personal biases I may have had in my original post. That being said, let's get down to it!

Formated for Use

Use this link for the video reference ==> https://www.youtube.com/watch?v=2vG9UTTPneQ

# Each second in the video reference has 25 frames #

$$ 1 Frame = 0.04 second

# The values taken for Englefield house's dimensions (X-Mansion filming site) are taken from google map's satellite images #

$$ Width: 36.26 meters

$$ Length: 49.59 meters

$$ Avg Distance: 42.88 meters

# We know the explosion happened inside the house but not the specific point! Let us assume that it took place from the farthest most corner, thus allowing for maximum time (Low-Balling). Let us take an average of the Length and Width to estimate how much distance the explosion was expected to have traveled (Which in this case is 42.88 meters). We now have a good approximation of the distance the explosion has to cover, but we still do not know the detonation velocity. Wikipedia to the rescue! Using Wikipedia we can find out a list of detonation velocities, and from this list we can easily find both the highest and the lowest detonation velocities (They are listed down below) #

$$ Detonation Velocities (Low-Ball): 2700 m s^(-1)

$$ Detonation Velocities (High-Ball): 10100 m s^(-1)

# We now have the two velocities and the constant distance. From this we can acquire two different values of the time taken for the explosion to cover the distance of the mansion (Also listed down below) #

$$ Time of Explosion (Low-Ball): (42.88/2700) seconds

$$ Time of Explosion (High-Ball): (42.88/10100) seconds

# Now we know the time it would have taken for the explosion to cross the distance of the house, and from the video ref provided we can find how much time Quicksilver was able to perceive from his own perspective #

$$ Time of Regular Slow-Mo: (130 - 4) ==> [126] seconds

# The reason I cut out four seconds is because in the scene there are two instances where they show us Quicksilver's perspective while he is in "Super" Slow-Motion. Time tags for both these instances are [0:34] and [2:10]. Let us use both these pieces of information to find how much faster Quicksilver was (His speed factor) #

$$ Speed Factor(Low-Ball) = (126) / (42.88/2700) ==> [7,933]

$$ Speed Factor(High-Ball) = (126) / (42.88/10100) ==> [29,678]

# Pretty damn fast! But let us now try to find out some actual values for his speed (Values that are ridiculously) low-balled BTW. For this calculation we are going to use the number of people quicksilver saved from the mansion. Now we are going to make a few assumption to ensure that the speed values that I am about to calculate are to a certain extent ridiculously low-balled (They are listed down below) #

$$ All the people he saved were standing right next to the front door of the mansion

$$ Quicksilver is not goofing off at all and the only distance he covered is while moving back and forth to save people

$$ Quicksilver is carrying two people every time he goes in and out the mansion to save the people

$$ We are only taking account of the people he physically carried out of the mansion (And the one curtain run!)

# From the video we can see that he physically carries out 23 people (I'm including the dog in this!). He also has to make one trip for a curtain that he places so I'm including that as well (Sue me!). In other words, the minimum trips he would have to make to carry out all 23 people (and place one curtain) is 26 runs #

$$ Min No of Back + Forward trips Quicksilver has to make = 26

# This is of course assuming he takes two people at a time (The curtain does not count in this). Now let us make a few assumption on how far Quicksilver moved the people out of the mansion, from the front door #

$$ 50 meters (Low-Ball)

$$ 100 meters (Med-Ball)

$$ 200 meters (High-Ball)

# Now to find the total distance #

$$ Total Distance (Low-Ball) = 26 * 50 meters

$$ Total Distance (Med-Ball) = 26 * 100 meters

$$ Total Distance (High-Ball) = 26 * 200 meters

# We have three different distances and two different possible times. Let us see what possible speeds we can make from these six values. What we get is . . . #

$$ Speed (Low-Balled D.Velocity + Low-Balled Distance) = (26 * 50) / (42.88/2700) Mach 238

$$ Speed (Low-Balled D.Velocity + Med-Balled Distance) = (26 * 100) / (42.88/2700) Mach 477

$$ Speed (Low-Balled D.velocity + High-Balled Distance) = (26 * 200) / (42.88/2700) Mach 954

$$ Speed (High-Balled D.Velocity + Low-Balled Distance) = (26 * 50) / (42.88/10100) Mach 892

$$ Speed (High-Balled D.Velocity + Med-Balled Distance) = (26 * 100) / (42.88/10100) Mach 1785

$$ Speed (High-Balled D.Velocity + High-Balled Distance) = (26 * 200) / (42.88/10100) Mach 3570

# Now this is of course assuming that Quicksilver is doing all of what my assumptions said! It is fair to say that these values are pretty low-balled! However, for my last trick, I would like to bring a small, but important, detail to attention. Throughout the scene we can see Quicksilver run Super-Fast . . . While everything is slowed down . . . Yeah . . . The very first time we see it is just seconds into the video at time tag [0:21]. Playing the video frame by frame I was able to obtain the No of frames it took for him to cross the distance of the field #

$$ No of Frames = 10

$$ Time Period in Slow-Mo = 0.4 seconds

# Now the distance is a bit iffy! From the video, you can clearly see him running across a field with him starting behind a few trees, so I figured it would be easy to just take out the distance from google maps again. Unfortunately, as I was looking across the estate, there seems to be two fields that Quicksilver could have run across, one which is 120.83 meters, and the other which is 302.31 meters #

$$ Distance(Low-Balled): 120.83 meters

$$ Distance(High-Balled): 302.31 meters

# Now recall the fact that we have the "Speed Factor" that we calculated from before. Using the two distances and the speed factors, we get . . . #

$$ Speed in "Strained" Super Speed (Low-Balled S.Factor + Low-Balled Distance) = (120.83/0.4) * (7,933) ==> **6986 Mach**

$$ Speed in "Strained" Super Speed (High-Balled S.Factor + Low-Balled Distance) = (120.83/0.4) * (29,678) ==> **26136 Mach**

$$ Speed in "Strained" Super Speed (Low-Balled S.Factor + High-Balled Distance) = (302.31/0.4) * (7,933) ==> **17479 Mach**

$$ Speed in "Strained" Super Speed (High-Balled S.Factor + High-Balled Distance) = (302.31/0.4) * (29,678) ==> **65393 Mach**

# The four speed values calculated above may be his maximum speed while he is straining, which is clearly visible in the video whenever he uses his Super-Speed in his already slowed down time perception. So it is not something I would say is too far-fetched. If anything, you could use the 6986 Mach as his "confirmed maximum" speed since it relies on so many low-balling estimations that it is outright hard to reject it! Hope this helps!

-- DarkDementor101

Tags

@supermanforever: Hmm . . . . I'll have to look into this, but it is a nice catch by you regardless! Would you mind if I said that I disagree with your calculations. I have certain reasons as to why I did not include those calculations, but would you be okay if I posted them a bit later. I'm a bit busy write now, and writing all these posts in one go take a bit of time.

Regardless, hope you are well and good day!

-- DarkDementor101

@subline: Thanks for the compliment!

@balancedtruth: Oh right! Forgot to mention this is Pre-JL!

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