Ok, this was in debating the old Taer in another thread on battles, but since I already went through the work to post it there, I figured more might want to see it.

The total power needed was about 14,145,748,688 pounds of force to do what he did, feel free to correct any calculations if anyone wants as I am not a math teacher or hobbiest. And also feel free to ask some questions about it. I do know there are more exact formulas for things like distance/mass/velocity over X angle/etc, so this is the simplistic version.

Either way, 14 billion pounds of force to do just the top sliver of the moon and throw it like that, thought it was worth mentioning in it's own post. Here is an an excerpt from my main post over in the other thread in response to Kara's strength he was talking about.

To Taer

I decided to do the math since apparently you did not, on the moon feet. Because I knew it was lowballing, let me do some minimums. For a moon around any planet, regardless if it is our moon or not, to become a celestial sphere, it has to have a certain weight/gravity. Since it is obviously a sphere, and not some chunk of rock moon like Phobos, we can rule out a few things. For rocky type planets - the size needs to be about 600 cubic km before it starts to pull itself down into a spheroid. For malleable, easy to compact/shape materials, like ice - it becomes less. But even the lighter estimates, for things like pure ice celestial objects from a few bits of asteroids - what does that have? Oh, about 400 cubic km. Since I don't need to get what I think it is (a bit of gas/rock) by the looks of it, let us just go by the lowest possible denominator and see what it at least is - if not way more, which it probably is.

1 cubic km of ice = 919000.8212 kilograms = 2026050 lbs.

* 400 to get total poundage needed for spheroidal light estimate...

= 810,420,000 pounds.

The moon had to weigh AT LEAST 800+ million pounds, and probably much more than that, given that it didn't look like something that was of that material by the color of it.

To peel off to top layer, doing the math, since it is the crust, of at least the deepness of the largest rocks we saw - which were what, 15, 20 feet or so? Ok, let us go 15ft for the lower bracket again. Or 4.572 meters. We can use this later to find how much weight we are talking about, but first we need to find the equation for the complete sphere from the volume that we have. V =⁴⁄₃πr³, since we know 400 cubic km is V, let us find R. 400 = ⁴⁄₃πx³ = ⁴⁄₃π(4.570781)³ - so 4.570781 kilometer radius.

Now let us use that 4.572 meters. Which is 0.004572 in km... To find the space that the top slice of that size off the planet, we use the formulas V =⁴⁄₃πR³-⁴⁄₃πr³, or simpler V=⁴⁄₃π(R³-r³).

To find the other radius, we just have to subtract 0.004572 from 4.570781 to get our two radii for this equation. The answer to that is 4.566209. So to have the answer we need, that is a set of two radii of 4.566209 and 4.570781.

Plug in to the formula mentioned above... V=⁴⁄₃π((4.570781)³-(4.566209)³)

= 1.19911940158 cubic km of Thanos destroyed crust - minimum possible estimates. Let us get the poundage on that, from the numbers we had before. 1 cubic km = 2,026,050 pounds of ice (as one of the better materials for you in this debate). Now, what is 2026050*(1.19911940158)?

2,429,475.86357 pounds. At extreme range, and by the looks of the attack, low difficulty in pushing.

But this still doesn't give us the total strength, because this was actually moving it - because how he did it over the distance he did, made it very much more impressive.

Want to find the power required to move that much mass that far and faster?

Just to be conservative on you, I am just going to use a basic pulling force required set of formulas... And to be ultra conservative let say it was only a mile up in the atmosphere (even though, lol - should be more).... It took what, 10 seconds at slowest to get there? So that would be D^2/t^2 here, or 1mile=1609.34 meters, ((1609.34 meters above)^2)/(10seconds)^2 = 2589975.2356/100 = 25899.752356. Let's just round that, 25900. So Thanos needs to have an acceleration of 25900G just to get it from where it was to the avengers faces he was fighting in that amount of time... And now to factor in the mass to this.... Multiply that by the mass that is to be pulled to get the force of the gauntlet being used there... 25900*2,429,475.86357lbs = 62,923,424,866.5

Converting this over to pound force - 14,145,748,688.98168.

That is to move that mass of a couple million, that quickly, that far.

Ouch. You want to talk about million+ pound punches, this Thanos with the moon feat has a striking power of at least 14 BILLION POUNDS, and this is from all the LOWEST POSSIBLE ESTIMATES. From just the top 15 feet of crust ONLY.

Legit estimations for a more normal moon consistency, size to what it looks like, and a more realistic distance, and we have entered in absurd territory.

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