How much energy do you think DCEU Superman heat vision had in this scene ?????

Superman was able to melt majority part of the I beam in less than a second.

http://www.saginawpipe.com/i-beams_jr._beams.htm

Zod should be holding a I beam 7.8" flanger width I-beam which weights about 106 lbs/ft.

So Superman should have melted 1.8 m of I beam which weights about 283.6 kg of steel which should have 3.05 x 10^27 atoms approximately.

Since Superman's heat vision is almost close to twice the temperature of the boiling point of iron (since steel has 98%of iron) it's safe to say that it should have provided energy More than bond dessociation energy of steel which is 3.96 eV = 6.345 × 10^-19 joules.

http://aip.scitation.org/doi/abs/10.1063/1.4979679?journalCode=jcp

Energy required to melt 283.6 kg of steel = 6.345*3.05*10^8 = 1935000000 joules= 1.935 gigajoules .

So Superman Can Generate 3.8+ Gigajoules in per second.

Enough energy to microwave TV dinners in 5 minutes.

Impressive feat, doesn't require a calculation at all though.

^^

More than jet fuel.

Wow that's impressive. Doesn't get brought into forum battles often. Should change now.

Nice calc.

3 gigajoules a second is what though? Does it convert to kt?

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@stalker_2:

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Really funny

15 joules

4.2 gigajoules is 1 ton of TNT.

@a8612152: Sick