In the Secret Wars, the Beyonder takes a number of villains and heroes from Earth and put them on a planet to fight. During one of the early battles, a 150 billion ton mountain is dropped on the heroes and the Hulk is able to hold up the entire mountain by himself until they figure out how to get out.
The heck dude ? We all know that the World Breaker Hulk is far higher than a mountain-lifter but this is MCU Hulk, bruh !
@themadtitan6000: show me his best lifting feats and i'll tell you
threw a boulder weighing a few tons miles away and the above one^ with one arm after being severely injured by the gauntlet and there was water flowing in too(described as hundreds of gallons)
@themadtitan6000: show me his best lifting feats and i'll tell you
Well most of his strength feats are rather striking strengths than lifting strengths. The only thing i can ever recall is that he can push the mass of a Leviathan Chitauri and flipped it. Tho i watched Incredible Hulk but i still forgotten his feats from the movie.
threw a boulder weighing a few tons miles away and the above one^ with one arm after being severely injured by the gauntlet and there was water flowing in too(described as hundreds of gallons)
@themadtitan6000: show me his best lifting feats and i'll tell you
Well most of his strength feats are rather striking strengths than lifting strengths. The only thing i can ever recall is that he can push the mass of a Leviathan Chitauri and flipped it. Tho i watched Incredible Hulk but i still forgotten his feats from the movie.
the mass of the tauri ship is an unknown quantity and forever on the vine people memed it at 3million tonnes which was absurd levels stupid considering an onway ramp rated for 200k tonnes held it
@abdulboriy: Class K means in the range of thousand tonnes, Class M means in the range of million tonnes, Class G means in the range of billion tonnes, Class T means in the range of trillion tonnes, Class P means in the range of quadrillion tonnes, Class E means in the range of quintillion tonnes, Class Z means in the range of sextillion tonnes and Class Y means in the range of septillion tonnes. Hope this makes you understand
Calculating distance of your example from Speed * Time
D = S * T
speed: 28.74 m/s time: 3.883 s
Distance = 111.59 m
Calculating force of the boulder throw
(pebble)
F = M * A
mass: 2,469.6 kg acceleration: (28.47 m/s - 0) 28.47 m/s2
force = 70,309.51 Newtons (gabbro)
F = M * A
mass: 5,145 kg acceleration: (28.47 m/s - 0) 28.47 m/s2
force = 146,478.15 Newtons
** Newtons to KGF
(pebble)
70,309.51 (N) * 0.1019716213 - 7,169.57 KG
(7,169.57 KG /1000) 7.16 MT
(gabbro)
146,478.15 (N) * 0.1019716213 - 14,936.61 KG
(14,936.61 KG/ 1000) 14.93 MT
Results - Hulk demonstrated a lifting ability of 2.46 Metric Tonnes and exertion of 70,309.51 Newtons or 7.16 Metric Tonnes Force at lowest, and at highest - a lifting ability of 5.14 Metric Tonnes and exertion of 146,478.15 Newtons or 14.93 Metric tonnes Force.
the trajectory of the throw is meaningless when there's 0 context given. both being the initial throw and the end result from a few frames in a dark grainy cgi backdrop. there's nothing at all outside those 2 shots.
you cannot tell hulks elevation. you cannot tell the trajectory of the arc. you cannot tell anything outside of the initial throw and end result.
the acceleration from distance that has context and is calculable - is right there.
Results - Hulk demonstrated a lifting ability of 2.46 Metric Tonnes and exertion of 70,309.51 Newtons or 7.16 Metric Tonnes Force at lowest, and at highest - a lifting ability of 5.14 Metric Tonnes and exertion of 146,478.15 Newtons or 14.93 Metric tonnes Force.
you conflated 616 hulk with mcu hulk. you stated he held up the entire avengers center, which he didn't. then you threw out random headcanon numbers like a few thousand tonnes.
i've never seen someone be this wrong so many times in one thread.
this is what happens when u go only by textbook definitions 1st of all here the force applied by hulk is impulsive in nature so the acceleration automatically becomes not defined so the above equation cannot be applied here.
you cannot tell hulks elevation. you cannot tell the trajectory of the arc. you cannot tell anything outside of the initial throw and end result.
trajectory of the arc will be parabolic feel free to debate me on this one if u cannot tell the maximum height the rock reached in its subsequent motion so u will down right ignore the y component of velocity and still calculate acceleration really intelligent choice
the acceleration from distance that has context and is calculable - is right there
Results - Hulk demonstrated a lifting ability of 2.46 Metric Tonnes and exertion of 70,309.51 Newtons or 7.16 Metric Tonnes Force at lowest, and at highest - a lifting ability of 5.14 Metric Tonnes and exertion of 146,478.15 Newtons or 14.93 Metric tonnes Force.
for calculating the acceleration provided by the force hulk applied on the rock u assumed that the duration of force application is 1sec which is completely wrong on your part since the force is impulsive the time taken is much less than 1sec
you conflated 616 hulk with mcu hulk. you stated he held up the entire avengers center, which he didn't. then you threw out random headcanon numbers like a few thousand tonnes.
i've never seen someone be this wrong so many times in one thread.
dude I am not a mr perfect like u I do a lot mistakes
doesn't at all look like the volume of millions of gallons of water would entail unless what we see in the film isn't indicative of where its all coming from
which it might of been - because inside the majority of the water itself doesn't even seem to be exerting force from ontop of the rubble, but coming in all sides
eitherway if it truly is millions of gallons then 3800 tonnes is an understatement.
this is what happens when u go only by textbook definitions 1st of all here the force applied by hulk is impulsive in nature so the acceleration automatically becomes not defined so the above equation cannot be applied here.
trajectory of the arc will be parabolic feel free to debate me on this one if u cannot tell the maximum height the rock reached in its subsequent motion so u will down right ignore the y component of velocity and still calculate acceleration really intelligent choice
you cannot calculate its trajectory because the initial and end result of the scene is incalculable at elevation. the scenes shot shows 0 context and the camera on the throw is from an angle that we have no idea the elevation of arc.
for calculating the acceleration provided by the force hulk applied on the rock u assumed that the duration of force application is 1sec which is completely wrong on your part since the force is impulsive the time taken is much less than 1sec
the duration is irrelevent because the scene pixel calc'd shows us the distance the rock traversed in that frame.
speed equals distance divided by time.
force equals mass times acceleration.
with the context we have, both of those conditions can be met. speculating on trajectory is exactly that, speculating.
S = D/T
Distance: 10.06 m Time: 0.350 s
Speed = 28.74m/s
(pebble)
F = M * A
mass: 2,469.6 kg
acceleration: (28.47 m/s - 0) 28.47 m/s2
force = 70,309.51 Newtons
(gabbro)
F = M * A
mass: acceleration: (28.47 m/s - 0) 28.47 m/s2
5,145 kg
force = 146,478.15 Newtons
dude I am not a mr perfect like u I do a lot mistakes
clearly. your grasp on physics is tenous at best and throwing out unsubstantiated claims isn't how you debate.
@darkthunder: The water is'nt magically floating above Hulk, it's all around them but once the ceiling breaks it goes through the opening that has now been made
OT: Thor's in the 20,000 ton range so Hulk should be higher
even this simple equation is wrongly written by u correct equation
a= (vf - vi)/t
here t is the time in which velocity changes
and I was not talking about this equation the equation that has to be applied here is( integration(f dt)= delta P)
where f is assumed to be constant in this case but here f is impulsive that is why it is not possible to calculate the force since dp/dt is not defined for this case
you cannot calculate its trajectory because the initial and end result of the scene is incalculable at elevation. the scenes shot shows 0 context and the camera on the throw is from an angle that we have no idea the elevation of arc.
whatever is shown on in the scene doesn't matter because it is a fact that if a body is thrown at any angle other than 0 or p radians from the direction of earth's gravity follows parabolic trajectory if u want I will prove it for u
I agree with u that the max height the body reached is hard to predict because the scene was not clear but still some assumptions could be made .
speed equals distance divided by time.
force equals mass times acceleration.
with the context we have, both of those conditions can be met. speculating on trajectory is exactly that, speculating.
S = D/T
Distance: 10.06 m
Time: 0.350 sSpeed = 28.74m/s
(pebble)
F = M * A
mass: 2,469.6 kg
acceleration: (28.47 m/s - 0) 28.47 m/s2
force = 70,309.51 Newtons
(gabbro)
F = M * A
mass: acceleration: (28.47 m/s - 0) 28.47 m/s2
5,145 kg
force = 146,478.15 Newtons
here the magnitude of velocity that u r getting is only for x component (Vx) u have completely ignored y component of velocity without which total speed cannot be calculated and therefore total acceleration u r getting is also wrong
clearly. your grasp on physics is tenous at best and throwing out unsubstantiated claims isn't how you debate.
according to u if the things the other user is stating even though correct if u don't know then the other user is an idiot nice going lad
here's the scene, chief. show me your imaginary math on trajectory of the throw with the context given.
Loading Video...
i'll even spoonfeed you the HQ screengrabs.
i'll be waiting.
As said before doesn't matter if the picture is clear or not the trajectory of the body will be parabolic I can prove it with my so called imaginary maths
Another thing I don't like adding real world physics and mathematics in a fictional debate but since u r the first one who started it so I will play along
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