Ok, so because I got bored here are the figures for the train feat. For this it assumes a person is watching from the side of the tracks as she runs down the top of the train and jumps onto the bridge.
Let's mark a place as zero [the person watching from the side of the train] so that the distance the train travels is.
DT = 70 * t
where DT is the distance from the person measured along the tracks and t is the time in hours. Now the persons distance, DP, from that same person, is the distance of the train minus the speed s the person is running in the opposite direction or
DP = 70 * t - s * t = (70 - s ) * t
or, since DP is zero
s = 70 mph.
And, just because I'm still bored I will explain why the same cannot be said about the running along the inside of a plane moving at 600 miles per hour. First, to a person outside the plane watching from the ground the plane would go by in seconds. Second, even though you are running along the plane, the plane is still moving, you are not in the same place compared to the ground, you have lost many miles in that run. Whereas in her feat, she did not lose any ground. She ran fast enough that even though the train was moving at 70 miles per hour underneath her, she still was able to grab and hold onto the bridge.
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